If I print layer.toString() I get something like this:
com.bbn.openmap.layer.shape.ShapeLayer[US
Rivers,0,0,0x0,invalid,hidden,alignmentX=null,alignmentY=null,border=,flags=
0,maximumSize=,minimumSize=,preferredSize=]
Why does it get the prettyName as the layer.getName() shouldn't there be a
layer.getPrettyName() and layer.getName()?
The above example I have pretty name of this layer set to "US Rivers" and
the actual name of the layer (as defined in the openmap.properties) is
"usRivers".
I would much rather work with the actual name rather than the pretty name...
Is there a way to get to that or is it lost once it is inside the
LayerHandler?
~Ben
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Received on Tue Aug 03 2004 - 15:33:32 EDT